Integrand size = 39, antiderivative size = 331 \[ \int \frac {1}{(d+e x)^{5/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx=\frac {1}{3 \left (c d^2-a e^2\right ) (d+e x)^{5/2} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {7 c d}{12 \left (c d^2-a e^2\right )^2 (d+e x)^{3/2} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {35 c^2 d^2}{24 \left (c d^2-a e^2\right )^3 \sqrt {d+e x} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}-\frac {35 c^3 d^3 \sqrt {d+e x}}{8 \left (c d^2-a e^2\right )^4 \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}-\frac {35 c^3 d^3 \sqrt {e} \arctan \left (\frac {\sqrt {e} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{\sqrt {c d^2-a e^2} \sqrt {d+e x}}\right )}{8 \left (c d^2-a e^2\right )^{9/2}} \]
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Time = 0.16 (sec) , antiderivative size = 331, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.103, Rules used = {686, 680, 674, 211} \[ \int \frac {1}{(d+e x)^{5/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx=-\frac {35 c^3 d^3 \sqrt {e} \arctan \left (\frac {\sqrt {e} \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{\sqrt {d+e x} \sqrt {c d^2-a e^2}}\right )}{8 \left (c d^2-a e^2\right )^{9/2}}-\frac {35 c^3 d^3 \sqrt {d+e x}}{8 \left (c d^2-a e^2\right )^4 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}+\frac {35 c^2 d^2}{24 \sqrt {d+e x} \left (c d^2-a e^2\right )^3 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}+\frac {7 c d}{12 (d+e x)^{3/2} \left (c d^2-a e^2\right )^2 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}+\frac {1}{3 (d+e x)^{5/2} \left (c d^2-a e^2\right ) \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}} \]
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Rule 211
Rule 674
Rule 680
Rule 686
Rubi steps \begin{align*} \text {integral}& = \frac {1}{3 \left (c d^2-a e^2\right ) (d+e x)^{5/2} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {(7 c d) \int \frac {1}{(d+e x)^{3/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx}{6 \left (c d^2-a e^2\right )} \\ & = \frac {1}{3 \left (c d^2-a e^2\right ) (d+e x)^{5/2} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {7 c d}{12 \left (c d^2-a e^2\right )^2 (d+e x)^{3/2} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {\left (35 c^2 d^2\right ) \int \frac {1}{\sqrt {d+e x} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx}{24 \left (c d^2-a e^2\right )^2} \\ & = \frac {1}{3 \left (c d^2-a e^2\right ) (d+e x)^{5/2} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {7 c d}{12 \left (c d^2-a e^2\right )^2 (d+e x)^{3/2} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {35 c^2 d^2}{24 \left (c d^2-a e^2\right )^3 \sqrt {d+e x} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {\left (35 c^3 d^3\right ) \int \frac {\sqrt {d+e x}}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx}{16 \left (c d^2-a e^2\right )^3} \\ & = \frac {1}{3 \left (c d^2-a e^2\right ) (d+e x)^{5/2} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {7 c d}{12 \left (c d^2-a e^2\right )^2 (d+e x)^{3/2} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {35 c^2 d^2}{24 \left (c d^2-a e^2\right )^3 \sqrt {d+e x} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}-\frac {35 c^3 d^3 \sqrt {d+e x}}{8 \left (c d^2-a e^2\right )^4 \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}-\frac {\left (35 c^3 d^3 e\right ) \int \frac {1}{\sqrt {d+e x} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}} \, dx}{16 \left (c d^2-a e^2\right )^4} \\ & = \frac {1}{3 \left (c d^2-a e^2\right ) (d+e x)^{5/2} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {7 c d}{12 \left (c d^2-a e^2\right )^2 (d+e x)^{3/2} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {35 c^2 d^2}{24 \left (c d^2-a e^2\right )^3 \sqrt {d+e x} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}-\frac {35 c^3 d^3 \sqrt {d+e x}}{8 \left (c d^2-a e^2\right )^4 \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}-\frac {\left (35 c^3 d^3 e^2\right ) \text {Subst}\left (\int \frac {1}{2 c d^2 e-e \left (c d^2+a e^2\right )+e^2 x^2} \, dx,x,\frac {\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{\sqrt {d+e x}}\right )}{8 \left (c d^2-a e^2\right )^4} \\ & = \frac {1}{3 \left (c d^2-a e^2\right ) (d+e x)^{5/2} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {7 c d}{12 \left (c d^2-a e^2\right )^2 (d+e x)^{3/2} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {35 c^2 d^2}{24 \left (c d^2-a e^2\right )^3 \sqrt {d+e x} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}-\frac {35 c^3 d^3 \sqrt {d+e x}}{8 \left (c d^2-a e^2\right )^4 \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}-\frac {35 c^3 d^3 \sqrt {e} \tan ^{-1}\left (\frac {\sqrt {e} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{\sqrt {c d^2-a e^2} \sqrt {d+e x}}\right )}{8 \left (c d^2-a e^2\right )^{9/2}} \\ \end{align*}
Time = 0.75 (sec) , antiderivative size = 227, normalized size of antiderivative = 0.69 \[ \int \frac {1}{(d+e x)^{5/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx=\frac {-\sqrt {c d^2-a e^2} \left (8 a^3 e^6-2 a^2 c d e^4 (19 d+7 e x)+a c^2 d^2 e^2 \left (87 d^2+98 d e x+35 e^2 x^2\right )+c^3 d^3 \left (48 d^3+231 d^2 e x+280 d e^2 x^2+105 e^3 x^3\right )\right )-105 c^3 d^3 \sqrt {e} \sqrt {a e+c d x} (d+e x)^3 \arctan \left (\frac {\sqrt {e} \sqrt {a e+c d x}}{\sqrt {c d^2-a e^2}}\right )}{24 \left (c d^2-a e^2\right )^{9/2} (d+e x)^{5/2} \sqrt {(a e+c d x) (d+e x)}} \]
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Time = 2.86 (sec) , antiderivative size = 549, normalized size of antiderivative = 1.66
method | result | size |
default | \(\frac {\sqrt {\left (c d x +a e \right ) \left (e x +d \right )}\, \left (105 \,\operatorname {arctanh}\left (\frac {e \sqrt {c d x +a e}}{\sqrt {\left (e^{2} a -c \,d^{2}\right ) e}}\right ) \sqrt {c d x +a e}\, c^{3} d^{3} e^{4} x^{3}+315 \,\operatorname {arctanh}\left (\frac {e \sqrt {c d x +a e}}{\sqrt {\left (e^{2} a -c \,d^{2}\right ) e}}\right ) \sqrt {c d x +a e}\, c^{3} d^{4} e^{3} x^{2}+315 \,\operatorname {arctanh}\left (\frac {e \sqrt {c d x +a e}}{\sqrt {\left (e^{2} a -c \,d^{2}\right ) e}}\right ) \sqrt {c d x +a e}\, c^{3} d^{5} e^{2} x -105 \sqrt {\left (e^{2} a -c \,d^{2}\right ) e}\, c^{3} d^{3} e^{3} x^{3}+105 \,\operatorname {arctanh}\left (\frac {e \sqrt {c d x +a e}}{\sqrt {\left (e^{2} a -c \,d^{2}\right ) e}}\right ) \sqrt {c d x +a e}\, c^{3} d^{6} e -35 \sqrt {\left (e^{2} a -c \,d^{2}\right ) e}\, a \,c^{2} d^{2} e^{4} x^{2}-280 \sqrt {\left (e^{2} a -c \,d^{2}\right ) e}\, c^{3} d^{4} e^{2} x^{2}+14 \sqrt {\left (e^{2} a -c \,d^{2}\right ) e}\, a^{2} c d \,e^{5} x -98 \sqrt {\left (e^{2} a -c \,d^{2}\right ) e}\, a \,c^{2} d^{3} e^{3} x -231 \sqrt {\left (e^{2} a -c \,d^{2}\right ) e}\, c^{3} d^{5} e x -8 \sqrt {\left (e^{2} a -c \,d^{2}\right ) e}\, a^{3} e^{6}+38 \sqrt {\left (e^{2} a -c \,d^{2}\right ) e}\, a^{2} c \,d^{2} e^{4}-87 \sqrt {\left (e^{2} a -c \,d^{2}\right ) e}\, a \,c^{2} d^{4} e^{2}-48 \sqrt {\left (e^{2} a -c \,d^{2}\right ) e}\, c^{3} d^{6}\right )}{24 \left (e x +d \right )^{\frac {7}{2}} \left (c d x +a e \right ) \left (e^{2} a -c \,d^{2}\right )^{4} \sqrt {\left (e^{2} a -c \,d^{2}\right ) e}}\) | \(549\) |
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Leaf count of result is larger than twice the leaf count of optimal. 781 vs. \(2 (293) = 586\).
Time = 0.67 (sec) , antiderivative size = 1584, normalized size of antiderivative = 4.79 \[ \int \frac {1}{(d+e x)^{5/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx=\text {Too large to display} \]
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\[ \int \frac {1}{(d+e x)^{5/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx=\int \frac {1}{\left (\left (d + e x\right ) \left (a e + c d x\right )\right )^{\frac {3}{2}} \left (d + e x\right )^{\frac {5}{2}}}\, dx \]
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\[ \int \frac {1}{(d+e x)^{5/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx=\int { \frac {1}{{\left (c d e x^{2} + a d e + {\left (c d^{2} + a e^{2}\right )} x\right )}^{\frac {3}{2}} {\left (e x + d\right )}^{\frac {5}{2}}} \,d x } \]
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Time = 0.49 (sec) , antiderivative size = 528, normalized size of antiderivative = 1.60 \[ \int \frac {1}{(d+e x)^{5/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx=-\frac {1}{24} \, {\left (\frac {105 \, c^{3} d^{3} e \arctan \left (\frac {\sqrt {{\left (e x + d\right )} c d e - c d^{2} e + a e^{3}}}{\sqrt {c d^{2} e - a e^{3}}}\right )}{{\left (c^{4} d^{8} {\left | e \right |} - 4 \, a c^{3} d^{6} e^{2} {\left | e \right |} + 6 \, a^{2} c^{2} d^{4} e^{4} {\left | e \right |} - 4 \, a^{3} c d^{2} e^{6} {\left | e \right |} + a^{4} e^{8} {\left | e \right |}\right )} \sqrt {c d^{2} e - a e^{3}}} + \frac {48 \, c^{3} d^{3} e}{{\left (c^{4} d^{8} {\left | e \right |} - 4 \, a c^{3} d^{6} e^{2} {\left | e \right |} + 6 \, a^{2} c^{2} d^{4} e^{4} {\left | e \right |} - 4 \, a^{3} c d^{2} e^{6} {\left | e \right |} + a^{4} e^{8} {\left | e \right |}\right )} \sqrt {{\left (e x + d\right )} c d e - c d^{2} e + a e^{3}}} + \frac {87 \, \sqrt {{\left (e x + d\right )} c d e - c d^{2} e + a e^{3}} c^{5} d^{7} e^{3} - 174 \, \sqrt {{\left (e x + d\right )} c d e - c d^{2} e + a e^{3}} a c^{4} d^{5} e^{5} + 87 \, \sqrt {{\left (e x + d\right )} c d e - c d^{2} e + a e^{3}} a^{2} c^{3} d^{3} e^{7} + 136 \, {\left ({\left (e x + d\right )} c d e - c d^{2} e + a e^{3}\right )}^{\frac {3}{2}} c^{4} d^{5} e^{2} - 136 \, {\left ({\left (e x + d\right )} c d e - c d^{2} e + a e^{3}\right )}^{\frac {3}{2}} a c^{3} d^{3} e^{4} + 57 \, {\left ({\left (e x + d\right )} c d e - c d^{2} e + a e^{3}\right )}^{\frac {5}{2}} c^{3} d^{3} e}{{\left (c^{4} d^{8} {\left | e \right |} - 4 \, a c^{3} d^{6} e^{2} {\left | e \right |} + 6 \, a^{2} c^{2} d^{4} e^{4} {\left | e \right |} - 4 \, a^{3} c d^{2} e^{6} {\left | e \right |} + a^{4} e^{8} {\left | e \right |}\right )} {\left (e x + d\right )}^{3} c^{3} d^{3} e^{3}}\right )} e \]
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Timed out. \[ \int \frac {1}{(d+e x)^{5/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx=\int \frac {1}{{\left (d+e\,x\right )}^{5/2}\,{\left (c\,d\,e\,x^2+\left (c\,d^2+a\,e^2\right )\,x+a\,d\,e\right )}^{3/2}} \,d x \]
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